### Abstract

A random variable Y is called an independent symmetrizer of a given random variable X if (a) it is independent of X and (b) the distribution of X+ Y is symmetric about 0. In cases where the distribution of X is symmetric about its mean, it is easy to see that the constant random variable Y = -EX is a minimum-variance independent symmetrizer. Taking Y to have the same distribution as -X clearly produces a symmetric sum, but it may not be of minimum variance. We say that a random variable X is symmetry resistant if the variance of any symmetrizer, Y, is never smaller than the variance of X. Let A' be a binary random variable: P{X = a} = p and P{X = b} = q, where ab, 0 < p < 1, and q = 1 -p. We prove that such a random variable is symmetry resistant if (and only if) p 1/2. Note that the minimum variance as a function of p is discontinuous at p = 1/2. Dropping the independence assumption, we show that the minimum variance reduces to pq -min(p, q)/2, which is a continuous function of p.

Original language | English (US) |
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Pages (from-to) | 1013-1020 |

Number of pages | 8 |

Journal | Bernoulli |

Volume | 5 |

Issue number | 6 |

DOIs | |

State | Published - Jan 1 1999 |

### All Science Journal Classification (ASJC) codes

- Statistics and Probability

### Keywords

- Binary random variables
- Linear programming
- Symmctrization

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## Cite this

*Bernoulli*,

*5*(6), 1013-1020. https://doi.org/10.2307/3318557