Abstract
Suppose ε > 0 and k > 1. We show that if n > n0(k, ε) and A ⊆ Zn satisfies |A| > (( 1 k) + ε)n then there is a subset B ⊆ A such that 0 < |B| ≤ k and Σb∈Bb = 0 (in Zn). The case k = 3 solves a problem of Stalley and another problem of Erdös and Graham. For an integer m > 0, let snd(m) denote the smallest integer that does not divide m. We prove that for every ε > 0 there is a constant c = c(ε) > 1, such that for every n > 0 and every m, n1 + ε ≤ m ≤ n2 log2n every set A ⊆ {1, 2,..., n} of cardinality |A| > c · n snd(m) contains a subset B ⊆ A so that Σb∈Bb = m. This is best possible, up to the constant c. In particular it implies that for every n there is an m such that every set A ⊆ {1,...,n} of cardinality |A| > cn log n contains a subset B ⊆ A so that Σb∈Bb = m, thus settling a problem of Erdös and Graham.
Original language | English (US) |
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Pages (from-to) | 196-205 |
Number of pages | 10 |
Journal | Journal of Number Theory |
Volume | 27 |
Issue number | 2 |
DOIs | |
State | Published - Oct 1987 |
Externally published | Yes |
All Science Journal Classification (ASJC) codes
- Algebra and Number Theory