Abstract
It takes n2/4 cliques to cover all the edges of a complete bipartite graph Kn/2,n/2, but how many cliques does it take to cover all the edges of a graph G if G has no Kt,t induced subgraph? We prove that O(n2−1/(2t)) cliques suffice for every n-vertex graph; and also prove that, even for graphs with no stable set of size four, we may need more than linearly many cliques. This settles two questions discussed at a recent conference in Lyon.
| Original language | English (US) |
|---|---|
| Article number | 103909 |
| Journal | European Journal of Combinatorics |
| Volume | 118 |
| DOIs | |
| State | Published - May 2024 |
All Science Journal Classification (ASJC) codes
- Discrete Mathematics and Combinatorics
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